(1+x/10)^2-2.1=0

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Solution for (1+x/10)^2-2.1=0 equation: 


x in (-oo:+oo)

(x/10+1)^2-2.1 = 0

(1/10*x+1)^2-2.1 = 0

(1/10*x+1)^2-2.1 = 0

1/100*x^2+1/5*x-1.1 = 0

1/100*x^2+1/5*x-1.1 = 0

1/100*x^2+1/5*x-1.1 = 0

DELTA = (1/5)^2-(-1.1*1/100*4)

DELTA = 0.084

DELTA > 0

x = (0.084^(1/2)-1/5)/(1/100*2) or x = (-0.084^(1/2)-1/5)/(1/100*2)

x = 50*(0.084^(1/2)-1/5) or x = -50*(0.084^(1/2)+1/5)

(x+50*(0.084^(1/2)+1/5))*(x-50*(0.084^(1/2)-1/5)) = 0

(x+50*(0.084^(1/2)+1/5))*(x-50*(0.084^(1/2)-1/5)) = 0

( x+50*(0.084^(1/2)+1/5) )

x+50*(0.084^(1/2)+1/5) = 0 // - 50*(0.084^(1/2)+1/5)

x = -(50*(0.084^(1/2)+1/5))

x = -50*(0.084^(1/2)+1/5)

( x-50*(0.084^(1/2)-1/5) )

x-50*(0.084^(1/2)-1/5) = 0 // + -50*(0.084^(1/2)-1/5)

x = -(-50*(0.084^(1/2)-1/5))

x = 50*(0.084^(1/2)-1/5)

x in { -50*(0.084^(1/2)+1/5), 50*(0.084^(1/2)-1/5) }

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